Why Does Coulomb's Law Give Different Results for the Same Charges?

AI Thread Summary
Coulomb's Law calculations for three charged objects reveal discrepancies in force direction and magnitude. The user calculated the net force on charge B as 2.8N to the right, while the textbook states it should be 1.08N to the left. The confusion arises from the interactions between the charges, specifically the attraction between the negative charge B and the positive charge C. It is suggested that either the user misread the problem or the textbook contains an error regarding the forces involved. Clarification on the signs and interactions of the charges is essential for accurate calculations.
anna sung
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Homework Statement

three objects carrying charges of (a)-4x10^-6 C, (B)-6x10^-6 C, and (c)+9x10^-6 C are placed in a line equally spaced from left to right by a distance of 0.5m. calculate the magnitude and direction of the net force acting on each.

Homework Equations



Force of the magnitude of B(-6x10^-6 C) the answer is 1.08N left
but I am getting 2.8N right

The Attempt at a Solution



Fba= 0.864 N (right)
Fbc = 1.944 N (right)

fnet = 0.864N (right) + 1.944N (right)
= 2.8N right

i don't understand how the book got 1.944N (left) because that's what gives 1.08(left)

B is negative and C is positive so shouldn't B be attracted to C which is to the right?
please help me .
 
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anna sung said:

Homework Statement




three objects carrying charges of (a)-4x10^-6 C, (B)-6x10^-6 C, and (c)+9x10^-6 C are placed in a line equally spaced from left to right by a distance of 0.5m. calculate the magnitude and direction of the net force acting on each.

Homework Equations



Force of the magnitude of B(-6x10^-6 C) the answer is 1.08N left
but I am getting 2.8N right

The Attempt at a Solution



Fba= 0.864 N (right)
Fbc = 1.944 N (right)

fnet = 0.864N (right) + 1.944N (right)
= 2.8N right

i don't understand how the book got 1.944N (left) because that's what gives 1.08(left)

B is negative and C is positive so shouldn't B be attracted to C which is to the right?
please help me .

As you realize, the only way to get that is if the charge on C is the same sign as the charge on B.
Either you have mis-read, or they have mis-printed.
 
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