Why Does Fission of U235 Release More Energy Than Calculated?

  • Thread starter Thread starter bphiz
  • Start date Start date
  • Tags Tags
    Fission
bphiz
Messages
2
Reaction score
0
Hi all

I am struggling with the fission of U235 into Barium 144 and Krypton 89.

U= 235.044u +(1.0087 mass of neutron)=236.053

Ba=(143.923) + (Kr=88.917) +3(1.0087u)

This leaves 0.186u missing on the products side.

If this is converted to MeV I gain the value, 173MeV. This agrees with various sources on the difference in binding energy of the different isotopes.

HOWEVER most sources then go onto say that in a single fission reaction more than 200 MeV is released per fission reaction. I can not reach this number at all. Even accounting for neutrino's making some of that energy inaccessible.My second problem is I can not really wrap my head around the concept this releasing energy...

With fusion, the mass of the products and the binding energy required is less than that of the constituent particles, therefore the missing mass manifests itself as energy, easy.

However even though the binding energy per nucleon is less for Uranium:

Binding energy for an entire uranium atom 1783MeV,
Krypton 766.909MeV
Barium 1190MeV

(I looked up those binding energies and they came out slightly differently to how I calculated them using (no of protonsx1.0073)+(no of neutrons) - mass of nuclues)

The binding energy required to hold the products together is HIGHER, than the energy required to hold uranium together.

Somebody please help explain this to me:(
 
Physics news on Phys.org
Binding energies are negative, so the higher binding energies of the products mean that energy is released.

Binding energy is not something you have to put into 'glue' the constituents together, it is actually a measure of the energy you would have to put into drag them apart. The (strong) nucelar force is sufficient to overcome the electrostatic force with a little bit to spare; that difference is what constitutes the binding energy.
 
Last edited:
Thankyou

So why the MeV different then? 173 produced to upwards of 200?
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top