Why Does My BJT Simulation Show Different Collector Current Than Calculated?

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The discussion centers on discrepancies between simulated and calculated collector current (Ic) in a BJT circuit. The calculated Ic of 22.12mA, derived from the formula Ic=βIb with β=175, significantly exceeds the simulated value of 1.64mA. The user struggles to understand this difference, particularly regarding the base current (Ib) calculation and the impact of Vce being approximately zero. It is noted that the transistor may be operating in a non-linear region or saturation, which affects the relationship between Ic and Ib. Understanding these operational states is crucial for accurate calculations and explanations in the report.
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1. As compared to the circuit as shown in the figure, i applied KCL in the circuit and still couldn't get the right Ic current at the collector as shown in the simulation.

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2. The IC current for XMM2 is 1.64mA but i got 22.12mA instead in my calculation. (I'm using the Ic=βIb where β=175 for the solution.)



3. Ib= Vcc-Vbe/20k Ib=3-0.7/20k Ib=0.115mA Ic=Ib (175) Ic=22.12mA

Any idea? Somehow, i need to explain it in my discussion for my report. I screwed up with the calculation and i have no idea of explaining the reason why Vce is approximately equal to 0 when there is a Ib current due to Vb voltage at its base.

More info, XMM1 shows the voltage of 77.205mV...
 
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You're operating the transistor in a non-linear region. Ic will not be β*Ib there.

Suppose that the transistor was driven into saturation (turned on as hard as it can go). Then the collector-emitter voltage would be just about zero (looks like an "ON" switch). What would be the voltage across R1? What then its current?
 

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