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BREAD
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Homework Statement
This is problem 6.5 in Griffiths EM.
I can't understand why dipole moment does not depend on coordinate systems.
Why does not dipole moment depend on coordinates system?
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SUMMARY
The dipole moment, denoted as \(\mathbf{p}\), is invariant under changes in the coordinate system, as established in Griffiths' "Introduction to Electrodynamics." The discussion clarifies that \(\mathbf{p}\) remains constant in space, leading to the conclusion that its spatial derivatives are zero. This invariance is a fundamental concept in electromagnetism, emphasizing that the dipole moment is a property of the charge distribution rather than the coordinate system used to describe it.
PREREQUISITES- Understanding of dipole moments in electromagnetism
- Familiarity with Griffiths' "Introduction to Electrodynamics"
- Basic knowledge of vector calculus
- Concept of spatial derivatives
- Study the derivation of dipole moments in Griffiths' EM
- Explore the implications of coordinate transformations in physics
- Learn about vector fields and their properties
- Investigate the relationship between charge distributions and their dipole moments
Students of electromagnetism, physics educators, and anyone seeking a deeper understanding of the properties of dipole moments and their independence from coordinate systems.
This is problem 6.5 in Griffiths EM.
I can't understand why dipole moment does not depend on coordinate systems.
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pasmith
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He's saying that [itex]\mathbf{p}[/itex] is constant in space, so its spatial derivatives vanish. Presumably this was stated in the problem statement.
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BREAD
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pasmith said:
There is not such presumption stated in problem .
The solution is saying that " Dipole moment P doesn't depend on coordinates system" is a generalized and obvious idea
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