Why Does Shear Increase with Distance in Torque-Shear Calculations?

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Shear stress in torque-shear calculations increases with distance from the center of gravity (CG) due to the relationship defined by the Tr/J formula. This formula indicates that within a bolt pattern, the bolt farthest from the center of rotation experiences the highest shear stress. The confusion arises because, intuitively, one might expect that greater distance would require less force to resist torque. However, the constant torque applied leads to increased shear force on bolts further from the CG. Understanding this relationship clarifies why shear increases with distance in these calculations.
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For some reason I am having a hard time visualizing the torque-shear equation, specifically when it comes to finding shear in rivet patterns with a non-symmetric load. We have been using the Tr/J formula to find the shear in the individual bolts. However, with this equation with increasing distance from the CG the shear also goes up. This seems counter-intuitive.

For example.. think about torquing a bolt. The farther you are from the center of rotation the less force is required to produce a given torque... so why is the reverse not true? I.e. "Given a constant torque, the farther you are from torque center the less force required to resist it, therefore less stress is induced?"

I've never had a problem with this before but it's been bugging me today for some reason. Thanks.
 
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Your second paragraph is an analogy for comparing two bolt (rivet) patterns, whereas your first paragraph is a question regarding one given bolt pattern. Within a given bolt pattern, the highest shear stress (and therefore shear force) occurs on the bolt having the largest distance from the center of rotation, which is shown by the relation T*r/J.
 
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