Why Does T^2 Not Directly Correspond to L in Compound Pendulums?

AI Thread Summary
The relationship between the square of the period (T^2) and the length (L) in a simple pendulum does not hold for a compound pendulum due to differences in mass distribution. In a simple pendulum, the mass is concentrated at a single point, while in a compound pendulum, the mass is distributed along its length. This distribution affects the oscillatory motion and the effective length used in calculations. The time period of a compound pendulum is influenced by the distance from the pivot to the center of mass, rather than just the physical length. Understanding these differences is crucial for accurately analyzing the dynamics of compound pendulums.
Mike Shandon
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Hi, I am having some trouble with the following question, any help would be appreciated

1. Homework Statement


For a simple pendulum, T^2 is directly proportional to the length of the string (L)

Why is this not true for a compound pendulum?

Homework Equations



T= 2pi sqrt(l/g) [/B]

The Attempt at a Solution


[/B]
Could it be because the mass of a simple pendulum is concentrated at one point, while the mass of a compound pendulum is spread out
 
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Mike Shandon said:
Could it be because the mass of a simple pendulum is concentrated at one point, while the mass of a compound pendulum is spread out
for oscillatory motion the mean position at equilibrium is important-as oscillations results and sustains due to slight diturbance about the equilibrium and the time period is related to the distance between point of suspension and point of oscillation an effective length of the compound pendulum.
 
Mike Shandon said:
Could it be because the mass of a simple pendulum is concentrated at one point, while the mass of a compound pendulum is spread out
Yes. See https://en.m.wikipedia.org/wiki/Pendulum.
 
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