Why Does the Escape Velocity Decrease as Mass Increases in an Electric Field?

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Escape velocity in an electric field is derived from the equation \sqrt{\frac{2kQq}{rm}}, highlighting that as mass increases, escape velocity decreases. This phenomenon occurs because, unlike gravitational fields where gravitational mass and inertial mass are equivalent, electric forces do not depend on the mass of the object. Consequently, while kinetic energy (KE) and inertia increase with mass, the electric potential energy remains constant based on the charges involved. Thus, a larger mass requires more kinetic energy to achieve the same velocity, leading to a lower escape velocity in an electric field. Understanding this distinction is crucial for grasping the dynamics of escape velocity in different fields.
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Upon applying the method of finding escape velocity to the E-field, I end up with:

\sqrt{\frac{2kQq}{rm}}

What I don't understand, conceptually, is why escape velocity decreases as mass increases, in the electric field. What property is actually taking place here?
 
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More kinetic energy is invested in a mass for a given velocity if the mass is larger. When dealing with the gravitational field, the force providing the potential energy scaled with the mass, but the inertia and thus the KE of the moving mass also scaled with the mass. This is due to what's known as "the equivalence principle", wherein gravitational mass and inertial mass are numerically the same for all matter. The effects cancel in the equations and the mass of the "escaping" body drops out of the equation for escape velocity.

With the electric scenario there's no equivalence principle "hiding" the effect of the mass of the moving object in the relationship. The electric force does not depend upon the mass of the object in motion, but the inertia and thus KE still depend upon that mass. So, for a given v: small mass, small inertia and small KE. Large mass yields large inertia and KE. The electric potential energy change, which the KE must balance for asymptotic escape, remains fixed by the charges.
 
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You explained that very well. Thank you very much.
 
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