Why Does the Eye Diagram Exclude f2?

AI Thread Summary
The discussion centers on the exclusion of frequency f2 in the eye diagram for a digital signal transmitted through a bandwidth-limited line. Participants seek clarification on why only f1 and f3 are considered in the answer, rather than including f2. The underlying principle is that the bandwidth limitation affects the frequencies that can effectively pass through, leading to the omission of f2. The conversation also touches on the frequency domain spectrum of a square wave, indicating a need for further explanation. Overall, the focus remains on understanding the reasons behind the frequency exclusions in the context of signal transmission.
fran1942
Messages
80
Reaction score
0

Homework Statement



draw the eye diagram you would expect to see should a digital signal be passed through a transmission line with a bandwidth limited to three times the maximum bit rate of the digital signal.

the answer is "Only f1 and f3 pass through"

My question is, what about f2 ?
Why does the answer to this question read f1 & f3 rather than f1 - f3 (including f2) ?

Thanks for any clarification.
 
Physics news on Phys.org
fran1942 said:

Homework Statement



draw the eye diagram you would expect to see should a digital signal be passed through a transmission line with a bandwidth limited to three times the maximum bit rate of the digital signal.

the answer is "Only f1 and f3 pass through"

My question is, what about f2 ?
Why does the answer to this question read f1 & f3 rather than f1 - f3 (including f2) ?

Thanks for any clarification.

What is the frequency domain spectrum for a square wave in the time domain?
 
Hello, thanks for your help. I have tried thinking about this one, but I still can't understand why f2 is not mentioned in the answer to this question.

If you could please offer some further explanation that would be great.
Thank you.
 
fran1942 said:
Hello, thanks for your help. I have tried thinking about this one, but I still can't understand why f2 is not mentioned in the answer to this question.

If you could please offer some further explanation that would be great.
Thank you.

You didn't address my question/hint. Try Googling my question if nothing still comes to mind...
 
Back
Top