Why does the heavier spade have a lower acceleration in soil?

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The discussion explores why a heavier spade experiences lower acceleration in soil compared to a lighter one, referencing Newton's laws of motion and the concepts of force and resistance. It highlights that before impact, the only force acting is the weight of the spade, while after impact, soil resistance plays a significant role in deceleration. The equation derived from Newton's Second Law, mg - R = ma, indicates that as mass (m) increases, acceleration (a) decreases. This relationship shows that a heavier spade will decelerate more significantly due to greater resistance relative to its weight. Understanding these principles clarifies the dynamics of how different weights affect acceleration in soil.
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"2 spades of the same type are dropped form the same height into the same patch of soil. why does the heavier spade have a lower acceleration in the soil than the lighter spade?"
 
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Hi and welcome.
It might something to do with forces and masses. Think about Newton's laws of motion. Or you may like to consider Momentum. It depends upon your level of familiarity with Physics.
 
What is the nature of the acceleration before the spade hits the ground? How about once the spade is in the soil?
 
If we're not careful, the OP will just sit and watch as the full answer emerges so that he can just copy it down without thinking. We need to wait for a response now, I think.
 
Well. Forces wise, there's the weight and soil resistance. Before hitting the soil, it's just weight. After hitting the soil, it's hindered by resistance?

Ohh, Newton's Second Law of Motion?
 
Yews - Newton II: f=ma (rearrange it to get what you need)
How will the forces on the spades differ and how will the masses differ? That should tell you whether there will be any difference in the acceleration (slowing down, that is).
 
Ah I see it.
mg-R = ma
a = mg-R / m
When m increases, a decreases.
Which makes a more negative, bigger deceleration?

Naww, I am not sure. Should it be R-mg then?
 
It's mg-R, if you're considering 'down' as positive. This consistent if you were accelerating at mg.
So you got it. Good.
 
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