Why does the slope of a PT Graph equal the VT graph?

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    Graph Slope
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Homework Help Overview

The discussion revolves around the relationship between position-time (PT) graphs and velocity-time (VT) graphs in the context of kinematics. The original poster seeks to understand why the slope of a PT graph corresponds to the values represented in a VT graph.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definitions and implications of slope in the context of PT and VT graphs. Some clarify the types of graphs being discussed, while others question the meaning of slope and its relation to velocity.

Discussion Status

The discussion is active, with participants providing clarifications and exploring the definitions related to the graphs. There is an ongoing examination of the concept of slope and its significance in understanding the relationship between position and velocity.

Contextual Notes

There are some uncertainties regarding the specific types of graphs being referenced, as participants initially mention different graph types before converging on position-time and velocity-time graphs. This may indicate a need for clearer definitions or assumptions in the discussion.

am2010
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Can someone please explain this to me (please see title)? I understand how to compute it but why is this so?

Thanks
 
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You mean momentum-time graph and velocity-time graph?
 
or is it the pressure-temperature and volume-temperature graph for ideal gases?
 
I mean Position-Time and Velocity-Time.
 
What does slope mean?

Slope = \frac{\Delta Y}{\Delta X}

What is your Y-axis? position (meters)
What is your X-axis? time (seconds)

Therefore,

Slope = position/time = meters/seconds = velocity

Velocity is the change of rate of change of position per unit time.
 

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