# Why does

## Main Question or Discussion Point

..fullwave bridge rectification raise the voltage *1.41? I scanned the net but I can't find an explanation as to why, only that it does..

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Remember, ac voltage is really regarding RMS voltage, and hence,
$$\sqrt{2}V_{rms}=V_p$$
where
$$\sqrt{2}=1.41.......$$

Aah, so basicly what's going on here is that the secondary ratings on transformers is given in RMS? and not peak?

Aah, so basicly what's going on here is that the secondary ratings on transformers is given in RMS? and not peak?
That's correct. Also note that a bridge rectifier will have the current passing through two diodes, so the output voltage will be 1.4 volts less than the peak.

Good! thank you both! the world now makes sense again