Why in hot weather dry streets can appear to be wet?

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In hot weather, dry streets can appear wet due to the temperature-dependent index of refraction of air, which creates layers of varying optical density. The hot air above the street is less dense than the warm air above it, leading to total reflectance that makes the street look like a mirror reflecting the sky. Observers may see reflections of the sky rather than objects like cars because the angles of reflection vary based on distance and perspective. This optical illusion is related to the phenomenon known as Fata Morgana, which can also cause objects to appear displaced or distorted. Understanding these principles of optics clarifies why such mirages occur on hot days.
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I'm studying interference and optics at the moment - can anyone explain why in hot weather dry streets can appear to be wet?

Thanks :smile:
 
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is this homework?

The key is that the index of refraction of air is temperature dependent.
 
Hello Steph,

directly above the street, there
is a layer of hot air, and above it, warm air.
The optical density of the hot air is smaller than that of the warm air.
Because of that, total reflectance occurs.
The street looks wet, because the light from the horizon sky doesn't
reach the street, but is directly reflected to your eye.
It's like looking into a mirror.



o_______________________[/color]o
__[/color]o___________________[/color]o
____[/color]o_______________[/color]o
______[/color]o___________[/color]o
________[/color]o_______[/color]o
__________[/color]o___[/color]o
____________[/color]o________[/color]WARM AIR[/color]
---------------------------------------------------
_____________________[/color]HOT AIR[/color] (optically thinner than above)
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_____________________[/color]STREET[/color]
 
Last edited:
Edgardo,
Your explanation leaves something to be desired. After responding to this question I was driving down a since straight road observing the "mirages" in the road ahead. By you explanation, since I was a significant distance down the road sitting in a pretty low car, and if the angle of reflection were equal to the angle of incidence, why was I observing the reflection of the sky and not oncoming cars on the other side of the mirage?
 
Hello Integral,

have you seen the sky-reflection in front of the car? Then
the angles are not equal as you say. However, my explanation is simplified,
since the index of refraction changes continuously (there are not just
two layers with different optical densities, but the optical density rather changes continuously).

I searched on google (keyword: Fata Morgana) and found this link:
http://www.schremmer.de/Atmosphare/Fata_morgana_1/body_fata_morgana_1.html
In these pics the reflections also show the cars.

The car, that you were observing, was it very far away?


@Steph: This phenomenon is also called a Fata Morgana
 
Thanks - that's been really interesting. I'd seen the idea of a tree appearing to be below the horizon, but I'd not linked the two together atall. I looked on google too and found lots of sites to read through - thanks.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
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