Why is Adding One Necessary in Binomial Series for 1/\sqrt{1-x^{2}}?

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When using a binomial series to expand 1/\sqrt{1-x^{2}} I come up with the correct answer except that I do not add the number one to my answer. Why do I have to add one to the series, should this not arise when calculating the sum?
 
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If x is zero the result is 1. You should definitely have a 1 in the series. What DID you do?
 
When expanding it I come up with the following result:

\sum (1*3* \ldots (2n-1)*x^{2n}) / 2^{n}n!

According to the answer key the answer is:

1 + \sum ((1*3* \ldots (2n-1)*x^{2n}) / 2^{n}n!)

Where does the one come from?
 
You didn't put limits on your summations. It looks like in the books answer the limits are 1 to infinity. In your answer they are 0 to infinity. Isn't 1 the n=0 term in your series?
 
Yes ... they separated out the n=0 term, because they thought the student would not understand the product 1\cdot3\cdots(-1)[/itex]
 
Thanks, I understand it now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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