Why is it the integral from a to b, but not a to c?

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The integral is calculated from a to b because this region represents the area between the capacitor plates where the electric field exists. Inside the conductors, such as the sphere and shell, there is no electric field, making the integral from a to c unnecessary. The integral represents a line integral of the electric field along a path, and since the electric force is conservative, the result remains consistent regardless of the chosen path. Integrating from a to c yields the same result, but the contribution from the region between b and c is zero. Therefore, the focus remains on the interval from a to b for calculating potential.
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Homework Statement



[PLAIN]http://img225.imageshack.us/img225/3342/unledyk.png





The Attempt at a Solution



The solution is posted with the problem.

My question is that why is the integral from a to b and not a to c? Why are they summining the potential from a to b?
 
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hello,

the region from a to b is the 'between the plates' part of the capacitor, so that is where the electric field can be found. both the sphere and shell are conductors so there will be no e-field inside those regions.

also, they are not 'summing the potential'; that is a line integral of the e-field over a path from the surface of the sphere to the inner surface of the shell. since the electric force is conservative, the result will be the same no matter what path is chosen.
 
Then what's wrong if you take the integral from a to c?
 
you can do that if you want, but the electric field between b and c is zero, so it will contribute nothing to the integral and you will get the same result.
 
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