Why Is Longitudinal Strain Zero for a Heated Copper Rod on a Smooth Surface?

AI Thread Summary
The discussion revolves around the longitudinal strain of a heated copper rod placed on a smooth surface. The calculation for strain suggests it should be non-zero due to thermal expansion, but the conclusion reached is that the strain is zero. This is attributed to the smooth surface, which does not provide any resistance to the rod's expansion. Participants express confusion over this result, suggesting a possible typo in the original question regarding whether it should refer to longitudinal stress instead. The consensus is that the unique conditions of the smooth surface lead to the absence of longitudinal strain.
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Homework Statement


A copper rod of length l_0 at 0 C is placed on a smooth surface.Now the rod is heated up to 100 C.FIND THE LONGITUDINAL STRAIN DEVELOPED ?

The Attempt at a Solution


What I did :
strain = delta l/ l_0
= l_0 alpha(coefficient of linear expansion) delta T/l_0
=100 alpha

but surprisingly the answer is zero and the solution says since the "SURFACE IS SMOOTH".
I have no clue why or how it works?
 
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I agree with your answer. The given answer makes sense if the question asked for longitudinal stress, so it may be a typo.
 
billy_joule said:
I agree with your answer. The given answer makes sense if the question asked for longitudinal stress, so it may be a typo.
Ditto.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

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