Why Is My Calculation of the Dielectric Constant Incorrect?

AI Thread Summary
The calculation of the dielectric constant is based on the formula k=q/(E*A*epsilon_0), where the charge q is 9.6 × 10^-7 C, the electric field E is 4.2 × 10^6 V/m, and the area A is 110 cm². The resulting dielectric constant calculated is approximately 2.3. Additionally, the induced charge on each dielectric surface can be determined using the equation q'=q(1-(1/k)), yielding a value of 5.4 × 10^-7 C. The discussion raises concerns about the accuracy of these calculations, suggesting a potential misunderstanding of the problem setup, particularly regarding the nature of the plates. Clarifying whether the plates are conducting or non-conducting is essential for accurate application of Gauss' law.
roro0505
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the answer i keep getting is wrong ... help?

Homework Statement



Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 4.2 × 106 V/m.

(a) Calculate the dielectric constant of the material.
(b) Determine the magnitude of the charge induced on each dielectric surface.


Homework Equations



k=q/(E*A*epsilon_0)

q'=q(1-(1/k))

The Attempt at a Solution



k=q/(E*A*epsilon_0)
=9.6E-7/(4.2E6*110E-4*8.85E-12)
=2.3

q'=q(1-(1/k))
=9.6E-7(1-(1/2.3))
=5.4E-7
 
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roro0505 said:
the answer i keep getting is wrong ... help?

Homework Statement



Two parallel plates of area 110 cm2 are given charges of equal magnitudes 9.6 × 10-7 C but opposite signs. The electric field within the dielectric material filling the space between the plates is 4.2 × 106 V/m.

(a) Calculate the dielectric constant of the material.
(b) Determine the magnitude of the charge induced on each dielectric surface.
It is not clear but I suspect that these are non-conducting plates, in which case Gauss' law is:

\oint E dA = E2A = \frac{Q}{k\epsilon_0}

AM
 
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