Why is my circuit nodal analysis not giving the correct I_sc value?

AI Thread Summary
The discussion focuses on difficulties in calculating the short-circuit current (I_sc) after removing a load and replacing it with a wire. The user applied super node analysis at nodes 1 and 4 and defined current directions but still arrived at an incorrect I_sc value of 8mA. They confirmed the error by comparing their result with Wolfram Alpha. The analysis indicates that node 2 is shorted to ground, leading to a specific voltage condition. The user seeks clarification on the correct approach to solve for I_sc accurately.
theBEAST
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Homework Statement


Capture.png


The Attempt at a Solution


Essentially I am having trouble with solving for I_sc when I remove the load and replace it with a wire.

I used a super node at 1 and 4 and also in my diagram I have defined the currents with directional arrows. I have been on this question for a long time and cannot get the correct answer which is I_sc = 8mA. I know it is wrong because I plugged it into wolfram alpha and ended up with the results as seen below.

From KCL:
photo_18.jpg


Where V1=a, V2=b, V3=c, I_sc=x and solving it gets:
idtsO.png
 
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V2 = 0, because node 2 is shorted to ground.
 
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