Why is the central fringe the brightest in diffraction patterns?

  • Thread starter Thread starter MarcL
  • Start date Start date
  • Tags Tags
    Diffraction
AI Thread Summary
The central fringe in diffraction patterns is brighter than other fringes due to the greater number of available scattering paths from the source. This results in a higher probability of photons being scattered at the central maximum, leading to increased brightness. The phenomenon is tied to the simplicity of the path combinations that contribute to the central maximum. Understanding this concept may require mathematical explanations for deeper insight. Overall, the central fringe's brightness is fundamentally linked to the physics of light scattering.
MarcL
Messages
170
Reaction score
2
The question is rather simple...

Why is the central fringe brighter in diffraction?
 
Physics news on Phys.org
Brighter than what? The other fringes?

The brightness depends on the number of photons scattered from the location (or the electric field incident).
This depends on things like the available paths.

http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/mulslid.html
... basically the central maximum involves the simplest combination of paths - so they are more likely to be taken, so more photons per unit time get scattered.

The details depend on the level you want the answer at.
I suspect this will be hard to describe without math.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top