Why is the direction of M_0 (r x F) out of the paper?

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The direction of M_0 (M_0 = r x F) is determined by the cross product of the position vector r and the force vector F, which results in a vector that is perpendicular to the plane formed by r and F. The reference point chosen in the figure significantly influences the direction of the position vector, and consequently, the torque. It is clarified that the direction of the moment can vary as long as it remains perpendicular to the plane created by r and F. The observer's perspective also plays a role in determining the direction of the position vector. Understanding these concepts is crucial for accurately determining the direction of torque in physics.
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I can't understand why the M_0 ( M_0 = r x F)is pointing in the direction out of the paper ?

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Based on the definition if torque:
$$M=r\times F$$
you can tell tell direction of torque by that of your position and the force.
The reference point the figure decided is important, which will influence the direction of the position hence torque also.
 
tommyxu3 said:
Based on the definition if torque:
$$M=r\times F$$
you can tell tell direction of torque by that of your position and the force.
The reference point the figure decided is important, which will influence the direction of the position hence torque also.
do you mean the direction of moment can be anywhere as long as it is perpendicular to the plane formed by r and F ?
 
goldfish9776 said:
the direction of moment can be anywhere as long as it is perpendicular to the plane formed by r and F ?
I think that is correct, for the choice of the origin's position depends on you and the direction of the vector of the position ##\vec{r}## depends on the observer.
 
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