Why is the reaction force in this direction?

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Neon32
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I want to understand why the reaction force of the short cable and link cable is in this direction? I want to understand it instead of memorizing. Your help would be much appreciated. Thanks in advance!
 
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  • Three diagrams of a beam pinned to a wall: one supported by a short cable, one by a short link, and one with a force of known line of action drawn as a red arrow pointing up and left.
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"Why?" Consider the resultant(s) for other directions.
 
From the point of view of the bar, something (the rope or link) is pulling it in that direction.

If you would analyze it from the rope or link point of view, the bar would be pulling on it and, thus, the direction would be in reverse.

Imagine yourself in tug of war, Who is pulling on the rope? From each team's point of view, it is the other team.

Teams of men in red and blue shirts pulling opposite ends of a thick rope during a tug of war at an outdoor event, with a spectator crowd and a hilltop castle behind.
 
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  • Teams of men in red and blue shirts pulling opposite ends of a thick rope during a tug of war at an outdoor event, with a spectator crowd and a hilltop castle behind.
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It's easy to understand the case with a rope... It can only provide a force in the same direction as the rope. It's less obvious with the short link but the answer is the pins at the end. Because both ends have pins the link cannot transmit a force in any other direction.
 
Neon32, it should help to take moments about one of the two ends, which are both pinned. The resultant moment must be zero, and that requires a certain ratio of the force components along the coordinate axes (Fx/Fy). That determines the direction of the resultant force.