Why is the value of EMF generated by a generator not zero at t = 0 s?

AI Thread Summary
At t = 0 s, the coil is indeed rotating, which means that even though it hasn't completed a rotation, it is in motion. This movement generates an electromotive force (emf) due to the principles of Faraday's Law, which states that emf is induced by changes in magnetic flux. The discussion clarifies that emf is related to the coil's motion rather than its static position. Therefore, the value of emf is not zero at t = 0 s. Understanding this concept is crucial for grasping the dynamics of electromagnetic induction.
songoku
Messages
2,467
Reaction score
382
Homework Statement
This is not homework.

Let say coil of generator is in horizontal position (i.e. the direction of magnetic field of the magnet is perpendicular to the normal vector of the plane of the coil). The coil is then rotated so emf will be induced on the coil.

If I draw the graph of Φ (magnetic flux) against time, the shape will be like sin wave and if I draw the graph of emf against time, the graph will be like negative cosine wave so it means that the starting point of graph of emf against time will a certain negative value (let say -5 V).
Relevant Equations
ε = - N . dΦ / dt
Does this mean that initially there will be emf induced on the coil at t = 0 s?

Initially, at t = 0 s, the coil has not been rotated yet so based on Faraday's Law, there won't be any change in magnetic flux so why the value of emf is not zero at t = 0 s?

Thanks
 
Physics news on Phys.org
songoku said:
at t = 0 s, the coil has not been rotated yet
No, but it is rotating. The emf is created by movement, not position.
 
  • Like
Likes Delta2 and songoku
haruspex said:
No, but it is rotating. The emf is created by movement, not position.
Thank you very much haruspex
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top