Why is the velocity of an H2 molecule after colliding with a 60nm photon so low?

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The final velocity of an H2 molecule after colliding with a 60nm photon is calculated to be around 3.5 m/s, which seems low given the high energy associated with the short wavelength. This low velocity is primarily due to the relatively large mass of the H2 molecule, which limits its acceleration despite the energy transfer from the photon. The discussion highlights a common misconception regarding the relationship between photon energy and molecular motion. Additionally, there are inquiries about the internal excitation energy of the H2 molecule post-collision. Understanding these concepts clarifies the dynamics of molecular interactions with high-energy photons.
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So if a H2 molecule collides with and absorbs a photon of wavelength around 60nm, I find the final velocity of H2 molecule (assuming momentum's conserved in collision) to be around 3.5 m/s, which I think is very small... I would have thought that since the wavelength of the photon is so small, the energy of it is pretty high, which means H2 should move much faster than just 3.5 m/s after the collision... it just doesn't make sense to me conceptually, I guess. Is there something wrong with my logic?
 
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Only in questioning your answer, which is correct.
The velocity is slow because H2 is so massive.
Preconception is the mother of confusion.
 
Hi. Just curious. What text did this question come out of? Are there any further questions about the internal excitation energy of the H2 molecule after the collision?
 
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