The discussion revolves around understanding the work done against friction in a physics problem involving a block being moved on a rough horizontal surface. The original poster expresses confusion regarding the relationship between the friction force and the work done against it.
Participants are actively engaging with the problem, attempting to clarify the concepts involved. Some have successfully calculated the friction force using Newton's second law, while others are considering different methods to find the further distance traveled by the block after the applied force ceases.
The problem involves a block with a specified mass and applied force, and participants are working within the constraints of the information provided, including the acceleration and the time the force is applied.
The obvious question is: What does the friction force equal?eureka_beyond said:why is the work done against friction =f x d and not 10N x d?
That means the 10 N force is no longer applied.eureka_beyond said:if the force ceases to act after 4 seconds,
What's the only force acting to slow down the block?what 's the further distance traveled by the block before it comes to rest?
Yes. Now use the given information to figure out the friction force. (Hint: Newton's 2nd law.)eureka_beyond said:that's got to be the friction, right?
Good!eureka_beyond said:by Newton's 2nd law
F=ma
Let the friction be f
10-f=3(2)
f=4N
Several ways:eureka_beyond said:yay! thanks a million. but there's another thing, how do I get the further distance traveled by the block before it comes to rest?