Why is the work done against friction not equal to the force times distance?

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The discussion revolves around understanding why the work done against friction is calculated as the friction force multiplied by distance, rather than using the applied force of 10N. The problem involves a 3 kg block moved by a 10N force, resulting in an acceleration of 2 m/s², and the friction force is determined to be 4N using Newton's second law. After the applied force ceases, the only force acting on the block is friction, which slows it down. To find the distance traveled before the block comes to rest, users suggest using kinematics or equating the work done by friction to the change in kinetic energy. This clarification helps in understanding the relationship between friction, force, and work in the context of the problem.
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Homework Statement


the question and answers are in the attachment, I don't understand question 8b) (ii), why is the work done against friction =f x d and not 10N x d?


Homework Equations





The Attempt at a Solution

 

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eureka_beyond said:
why is the work done against friction =f x d and not 10N x d?
The obvious question is: What does the friction force equal?
 
okay, the question goes like this:
on a rough horizontal Ground, a 3 kg block at rest is moved be a Force of 10N. The acceleration of the block is 2ms-2.
if the force ceases to act after 4 seconds,
what 's the further distance traveled by the block before it comes to rest?
 
eureka_beyond said:
if the force ceases to act after 4 seconds,
That means the 10 N force is no longer applied.
what 's the further distance traveled by the block before it comes to rest?
What's the only force acting to slow down the block?
 
that's got to be the friction, right?
 
eureka_beyond said:
that's got to be the friction, right?
Yes. Now use the given information to figure out the friction force. (Hint: Newton's 2nd law.)
 
by Newton's 2nd law
F=ma
Let the friction be f
10-f=3(2)
f=4N
 
eureka_beyond said:
by Newton's 2nd law
F=ma
Let the friction be f
10-f=3(2)
f=4N
Good!
 
yay! thanks a million. but there's another thing, how do I get the further distance traveled by the block before it comes to rest?
 
  • #10
eureka_beyond said:
yay! thanks a million. but there's another thing, how do I get the further distance traveled by the block before it comes to rest?
Several ways:
(1) You can find the acceleration and use kinematics. (First figure out how fast the block is moving at the end of 4 seconds.)
(2) You can set the work done by friction equal to the change in kinetic energy.
 
  • #11
ah, I see. The book must have been using the second way you describe, I get it now, thanks a lot.
 
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