Why is Vi - Vf used to calculate voltage in circuits?

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SUMMARY

The calculation of voltage across a circuit element is expressed as Vi - Vf, which represents the potential difference between the initial voltage (Vi) and the final voltage (Vf). This approach emphasizes the energy changes within circuit elements rather than the current's potential energy changes. The discussion highlights the confusion surrounding this notation and suggests that it is a matter of sign convention, where Vi - Vf equates to -(Vf - Vi). For further clarity, readers are encouraged to consult introductory circuit textbooks and resources on Kirchhoff's Voltage Law.

PREREQUISITES
  • Understanding of basic circuit theory
  • Familiarity with voltage and potential difference concepts
  • Knowledge of Kirchhoff's Voltage Law
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Read introductory circuit textbooks, such as "Fundamentals of Electric Circuits" by Alexander and Sadiku
  • Study Kirchhoff's Voltage Law in detail
  • Explore the concept of sign conventions in circuit analysis
  • Practice calculating voltage drops across various circuit elements
USEFUL FOR

Students in electrical engineering, educators teaching circuit theory, and anyone seeking to clarify voltage calculations in electrical circuits.

Miike012
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My question is why did they choose to calculate the voltage across a circuit element as vi - vf because it seems contradictory.
More detail is in the document.

Someone please answer because this has been bothering me.
THank you.
 

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My guess is that instead of calculating the potential energy drops/gains of current they are calculating the potential energy drops/gains of the circuit elements which is the negative of the potential energy drops/gains of current. It's just frustrating because the book doesn't explain why they are doing what they are doing. Are there any first semester circuits books that give explanations? The book I am reading from is
https://www.amazon.com/dp/0470633220/?tag=pfamazon01-20
 
If you use Vi-Vf then you would change the signs. Vi -Vf = -(Vf-Vi). When you calculated it you used Vf-Vi.

BTW, Vr1 + Vr2 - M = 0.

When you start at the bottom, you first go into the - side of the battery, and then into the + side of two resistors.

Read the wikipedia page on kirchhoffs voltage law.
 

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