Why Might Option B Be Correct in This Collision Problem?

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The discussion revolves around a collision problem where the original poster believes the answer should be option (A), but the question indicates option (B) is correct. A key point raised is the importance of considering the weight of the table, which adds a downward force of 2N. The total downward force is calculated to be 7N, leading to a leg reaction of 1.75N. Participants clarify that the 2N force from the collisions affects the entire table, emphasizing the need for accurate force accounting in the solution. The conversation highlights the significance of thorough analysis in collision problems.
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Hi friends,
I have an issue in solving a Collision Problem.
Please Help me in solving this.
Thank you all in advance.

The problem is as:

https://fbcdn-sphotos-c-a.akamaihd.net/hphotos-ak-frc3/q71/s720x720/1384332_1432382970322142_101322866_n.jpg


Attempt:

https://fbcdn-sphotos-d-a.akamaihd.net/hphotos-ak-ash3/q81/s720x720/994348_1432381503655622_646459501_n.jpg

So friends according to me the answer should be option (A) but according to question option, (B) is correct. Please try to help me in this.
I will appreciate the help.
 
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You didn't count with the weight of the table.

ehild
 
ehild said:
You didn't count with the weight of the table.

ehild

Ok, well that 0.5N.will act in the downward direction on the table. And weight of the table will be 0.2 x 10 = 2N.
Hence the total force would be 7 N. downward. On leg reaction would be 7/4 = 1.75N.
Is it correct?
 
coldblood said:
Ok, well that 0.5N.will act in the downward direction on the table. And weight of the table will be 0.2 x 10 = 2N.
Hence the total force would be 7 N. downward. On leg reaction would be 7/4 = 1.75N.
Is it correct?

2N force acts on the whole table because of the collisions. See your own solution in the first post.

ehild
 
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