Consider the system shown in the figure with m1 = 23.00 kg, m2 = 13.60 kg, R = 0.13 m, and the mass of the uniform pulley M = 5.00 kg. Object m2 is resting on the floor, and object m1 is 5.00 m above the floor when it is released from rest. The pulley axis is frictionless. The cord is light, does not stretch, and does not slip on the pulley.
KEi + Ugi = KEf + KEf(rotational) + Ugf
The Attempt at a Solution
Initially I keep trying to solve the problem by using free body diagrams and finding the acceleration. But all my answers were wrong.
However, I saw someone posted this question on yahoo answers and the solution he got was by using conservation of energy.
I do not see the difference in using the conservation of energy method and my method. Can someone enlighten me? This topic is killing me. haha
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