Why we draw the angle with y-axis?

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The discussion centers on the convention of drawing angles with respect to the y-axis when indicating vector direction. While it is technically acceptable to use any reference direction, clarity is essential, necessitating the indication of the chosen reference and the angle's sense. Standard practice typically involves measuring angles counterclockwise from the positive x-axis. If alternative references are used, it's important to clearly communicate this to avoid confusion. Overall, clarity in representation is crucial for effective communication in vector analysis.
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When we want to indicate the direction of a vector,why we draw the angle with the vertical (y-axis) side?
 

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Technically speaking, one can draw the angle with respect to any convenient reference direction... and, for clarity, you should somehow indicate that reference direction and sense (clockwise or counterclockwise). A clear diagram, as you've drawn, is fine.

Standard conventions usually use the counterclockwise angle from the positive x-axis. However, if you use anything else, do what I suggested above.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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