Why

AI Thread Summary
In a Newton's cradle, releasing one ball does not result in two balls on the opposite side moving at half the velocity due to the conservation of momentum and energy principles. If one ball with velocity v collides with two stationary balls, the expected outcome of both moving at velocity v/2 violates the conservation of kinetic energy. The equations set up for kinetic energy and momentum must reflect that the total energy before and after the collision remains constant. The discussion emphasizes the need to correctly apply these conservation laws to analyze the system. Understanding these principles is crucial for solving the problem accurately.
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Homework Statement


If one ball of a Newtons cradle is released at any velocity, why can't two balls on the other side be moved with half of the velocity of that ball.

Homework Equations


Law of consrvation of Energy and Low of conservation of Momentum


The Attempt at a Solution


Don't know where to start.
 
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Well, suppose this does happen and set up equations of conservation of kinetic energy and conservation of momentum. We have the situation in which one ball moves with velocity v before the collision, with two at rest, then two balls move with velocity v/2 after the collision, with the first at rest. Try setting up the equations.
 
Show how it violates Conservation of Energy
 
Thanks for the hint but I don't understand how to plug in two objects on one side and one on the other side in the equation.
 
Taking the expression for kinetic energy, note we are ignoring gravitational potential energy here since we are considering the velocity of the balls just after and before collision;

\underbrace{\frac{1}{2}mv^2}_{\text{First Ball}} = \underbrace{\frac{1}{2}mv'^2}_{\text{Second Ball}}+\underbrace{\frac{1}{2}mv'^2}_{\text{Third BallBall}}

Now, all you need to do is plug in the value for v', which is the velocity of the second two balls, and check the equality.
 
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