Will the Cart Roll Down the Hill Despite Friction?

AI Thread Summary
The cart, weighing 0.80 kg and rolling down a 30° hill from a height of 0.50 m, experiences a gravitational force component of 3.92 N. However, the frictional force opposing its motion is 5.0 N. Since the frictional force exceeds the gravitational force acting on the cart, it will not roll down the hill. The discussion clarifies that the frictional force is the maximum and not a constant, confirming that the cart will remain stationary. Therefore, the cart does not roll to the bottom of the hill.
rawr8712
Messages
1
Reaction score
0

Homework Statement


An 0.80-kg cart rolls down a 30.0° hill from a
vertical height of 0.50 m. The distance that the cart must roll to the bottom of
the hill is 0.50 m/sin 30.0°=1.0 m. The surface of
the hill exerts a frictional force of 5.0 N on the cart.
Does the cart roll to the bottom of the hill?

Homework Equations


I do know what equation to use or how to get the problem started.
f=ma

The Attempt at a Solution


F=9.8m/s^2(.8kg)
F=7.84N(sin30)
F=3.92N
so it doesn't over come the frictional force.
 
Last edited:
Physics news on Phys.org
Welcome to PF!

rawr8712 said:

Homework Statement


An 0.80-kg cart rolls down a 30.0° hill from a
vertical height of 0.50 m. The distance that the cart must roll to the bottom of
the hill is 0.50 m/sin 30.0°=1.0 m. The surface of
the hill exerts a frictional force of 5.0 N on the cart.
Does the cart roll to the bottom of the hill?

Hi rawr8712! Welcome to PF! :smile:

Yes, the downhill component of gravity is 3.92N, so if the friction force is 5N, the cart will accelerate uphill!. :rolleyes:

Are you sure you've copied the question accurately?​
 


tiny-tim said:
Hi rawr8712! Welcome to PF! :smile:

Yes, the downhill component of gravity is 3.92N, so if the friction force is 5N, the cart will accelerate uphill!. :rolleyes:

Are you sure you've copied the question accurately?​

the cart will not accelerate up the hill seeing as the force stated for friction is the maximum force that friction can exert not a constant. therefore the cart will not move
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top