Will the formation of a dative bond change the oxidation number?

AI Thread Summary
In the discussion about the oxidation number of nitrogen in ammonia (NH3) when it forms a dative bond with a hydrogen ion (H+) to create an ammonium ion (NH4+), it is clarified that the oxidation state of nitrogen does not change from +3 to +5. Instead, the oxidation number remains at -3 in NH3 and -3 in NH4+. The confusion arises from the bonding nature; while nitrogen shares electrons in the dative bond, the oxidation state is determined by the overall electron count and formal charge, not merely by the number of electrons involved in bonding. Thus, the oxidation number of nitrogen in both NH3 and NH4+ is consistently -3.
coconut62
Messages
161
Reaction score
1
Consider NH3, if it forms a dative bond with an H+ to form an ammonium ion, will the oxidation number of N change from +3 to +5? My reasoning is that it uses 5 electrons in bonding.

Is that correct?
 
Chemistry news on Phys.org
furthermore

NH_3

NH_4^+
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top