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Icedfire01
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Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
The distance formula for acceleration due to gravity is d = 1/2 * g * t^2, where d is the distance traveled, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and t is the time.
The distance formula for acceleration due to gravity is derived from the basic physics equation d = v0 * t + 1/2 * a * t^2, where v0 is the initial velocity and a is the acceleration. In the case of free fall due to gravity, the initial velocity is 0 and the acceleration is g, resulting in the simplified formula d = 1/2 * g * t^2.
The letter 'g' is used to represent acceleration due to gravity because it is the standard symbol for acceleration and is derived from the word "gravity". It is also a constant value (9.8 m/s^2) that is universally recognized in physics.
Yes, the distance formula for acceleration due to gravity can be used for objects falling from any height. This is because the formula takes into account the time of the fall, which is independent of the height.
Yes, the distance formula for acceleration due to gravity does not account for air resistance, which can affect the actual distance traveled by an object in free fall. The formula assumes that the object is falling in a vacuum, where there is no air resistance. In real-life scenarios, air resistance may decrease the acceleration due to gravity and therefore affect the distance traveled.