# Work and Kinetic Energy

1. Mar 29, 2014

### Richober

1. The problem statement, all variables and given/known data
An ice block is being pushed through a displacement d→=(15m)i -(12m)j along an embankment with rushing water. It exerts F→=(210N)i -(150N)J on block. How much work on block does force do?

2. Relevant equations
W=Fxd
Pythogoreum equation
a^2 +b^2= c^2

3. The attempt at a solution
I drew i and j coordinates for both displacement vector and force vector. I calculated
d→=15^2 + 12^2= c^2
d→=c=19.21m
I used same for F→
(210N)^2 + (150N)^2 = c^2
c=258.07 N
W=Fxd
(258.07N)* (19.21m) = 4957.52 J
I think I might have set it up wrong.

2. Mar 29, 2014

### SammyS

Staff Emeritus
Hello Richober. Welcome to PF !

What is the definition of work?

Not only are force, $\ \vec{F}\,,\$ and displacement, $\ \vec{d}\,,\$involved, their relative directions must also be included..