1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Work and Kinetic Energy

  1. Mar 29, 2014 #1
    1. The problem statement, all variables and given/known data
    An ice block is being pushed through a displacement d→=(15m)i -(12m)j along an embankment with rushing water. It exerts F→=(210N)i -(150N)J on block. How much work on block does force do?


    2. Relevant equations
    W=Fxd
    Pythogoreum equation
    a^2 +b^2= c^2



    3. The attempt at a solution
    I drew i and j coordinates for both displacement vector and force vector. I calculated
    d→=15^2 + 12^2= c^2
    d→=c=19.21m
    I used same for F→
    (210N)^2 + (150N)^2 = c^2
    c=258.07 N
    W=Fxd
    (258.07N)* (19.21m) = 4957.52 J
    I think I might have set it up wrong.
     
  2. jcsd
  3. Mar 29, 2014 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Hello Richober. Welcome to PF !

    What is the definition of work?

    Not only are force, ##\ \vec{F}\,,\ ## and displacement, ##\ \vec{d}\,,\ ##involved, their relative directions must also be included..
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Work and Kinetic Energy
  1. Kinetic Energy&Work (Replies: 4)

Loading...