Work- constant pressure, changing volume

AI Thread Summary
The work done by a gas during expansion from 1.0 L to 3.3 L at a constant pressure of 2.8 atm was initially calculated incorrectly. The pressure was converted to Pascals, resulting in 283710 Pa, and the work formula W = p(deltaV) was applied. However, the correct approach requires converting the volume to cubic meters and the pressure to kilopascals by multiplying by 101.3. After making these conversions, the calculation can be redone for an accurate result. Proper unit conversions are essential for obtaining the correct answer in physics problems.
physics1234
Messages
21
Reaction score
0
Find the work done by a gas when it is expanded from a volume of 1.0 L to 3.3 L at a constant pressure of 2.8 atm.

I converted the atm to Pascals by multiplying 2.8 x 101325 to get 283710.

Then I used the formula W=p(deltaV)

so 283710 x (3.3-1.0) = 652533

I don't understand why this is the wrong answer.
 
Physics news on Phys.org
Nevermind, I got it :-)

Thanks anyway!
 
hi brother
so as to your answer be at joule
you must convert the volume to cubic meter m3 , and to convert the pressure to kpa not pascal , by multiplying by 101.3 , try the new answer...

sorry my english is not so good
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Calculating ΔE Difference for 2 Samples of Monatomic Ideal Gas
Replies
4
Views
2K
Calculating Work Done by Gas at Constant Pressure
Replies
2
Views
2K
Air pressure changes in a vessel as the vessel volume increases
Replies
8
Views
931
Ideal Gas compressed at constant pressure
Replies
12
Views
5K
Convert J/mol k into atm cm^3/mol k
Replies
6
Views
7K
Gas temperature in a constant volume
Replies
8
Views
2K
Calculating work done by a gas
Replies
2
Views
706
Finding gauge pressure for gas inside light bulb as it heats up
Replies
6
Views
1K
When does gas do more work: constant pressure or temperature?
Replies
2
Views
2K
Thermodynamics: calculating work question
Replies
6
Views
2K

Hot Threads

Recent Insights

Back
Top