# Work done by an expanding gas with no moving boundary

1. Nov 13, 2009

### manuslum

Hello,

I'm trying to find an expression for the work done by a gas that expands adiabatically from one chamber to another through a controlled opening and closing of a valve.

The setup is the following. There is spherical bulb divided inside into to chambers. One of the chambers (A) contains a gas that is pressurized at several atmospheres, while the other chamber (B) contains very little of the gas, with a pressure that is only 1% of the pressure in chamber A. The two chambers are connected trough a small hole that has a valve on the side of chamber A, keeping the gas from flowing into chamber B. Upon command, the valve will open in small and regular time intervals that would allow some gas to escape from A into B.

I need to find the work that the gas will do on [anything] while expanding. Note that there is no boundary moving, like a piston or anything similar. I know that if there were such a boundary, I could use dW = P dV, but I can't seem to find the change in volume in my scenario. First I thought that the work would be the product of the Force and the Distance the gas covers while moving into chamber B (the thickness of the dividing plate inside the sphere), but I am now too doubtful about this assumption.

Also, I'm taking into account the fact that the force that the gas exerts on the valve is:

FNet = PAA - PBA = A(PA-PB), where PA is the pressure in chamber A, PB is the pressure in chamber B, and A is the cross-sectional area of the small hole connecting the two chambers (Pi R2)

I realize that this force is not constant as it depends on the relative pressures in A and B, which are changing during the duration of the entire process. I'm also trying to take this fact into account in my calculations.

What I ultimately intend to achieve is the cooling of chamber A, and to that end, I need to find a point (if it exists) where the temperature in A is a specific value. I believe that the work done by the gas while expanding will result in a decrease in its internal energy, which translates into a drop in temperature.