fd25t6
- 10
- 0
A 30-N box is pulled 6.0 m up along a 37 °inclined plane. What is the work done by the weight (gravitational force) of the box?
Ok so attempt goes like this:
W = FDCOS(37)
So force weight parallel to the plane is 30sin37 = 18.05N
" perppendicular " 30cos37= -23.95
add them up = -5.9n
so -5.9n(6m)cos37 = -28.3 Newtons?
is this right. Thanks in advance for the help
Ok so attempt goes like this:
W = FDCOS(37)
So force weight parallel to the plane is 30sin37 = 18.05N
" perppendicular " 30cos37= -23.95
add them up = -5.9n
so -5.9n(6m)cos37 = -28.3 Newtons?
is this right. Thanks in advance for the help