Work Done by Gravity: Formula & Considerations

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 3K views
alingy1
Messages
325
Reaction score
0
Let's say a ball falls from a height of 20m from the ground. g=9,8m/s^2. m=3kg.
Consider resistance of air in a qualitative way.

What's the formula for the work done by gravity?

So, I just thought about this question. I wonder if W=F*s should be applied. Does gravity still do 588J of work? Or should we take into account that F is smaller because of air friction? All this concept of work is very new to me and I googled for similar questions but couldn't find any web page alluding to my problem.
 
Physics news on Phys.org
If considering air resistance, then the net work is not the same as the work done by gravity, which is the same regardless of air resistance.

Your notion of W=F*S works if you treat gravity as an approximately constant force, but that approximation becomes poor as S gets larger. This all comes from the fact that the gravitational force on Earth or any other planet is actually given by Newton's Laws of Gravitation, which creates a more difficult work calculation.

You should also note that work is not simply F*S.

See: https://en.wikipedia.org/wiki/Work_(physics )
 
Last edited by a moderator:
alingy1 said:
Let's say a ball falls from a height of 20m from the ground. g=9,8m/s^2. m=3kg.
Consider resistance of air in a qualitative way.

What's the formula for the work done by gravity?

So, I just thought about this question. I wonder if W=F*s should be applied. Does gravity still do 588J of work? Or should we take into account that F is smaller because of air friction? All this concept of work is very new to me and I googled for similar questions but couldn't find any web page alluding to my problem.

The force due to gravity is the same, the distance fallen is the same, so the Work done by gravity should still be the same.
HOWEVER: the resistance of air will be doing some work too.
 
Okay, so, the total work done (not only by g) will be smaller than the work that should have been done without air. The air does negative work and g, the same work.
 
alingy1 said:
Okay, so, the total work done (not only by g) will be smaller than the work that should have been done without air. The air does negative work and g, the same work.

Correct. It is similar to pushing a box with friction opposing the push. You do work with your own force F_p as you move the block, while the ground also does work in the OTHER direction (different signs) with the frictional force F_f doing work as the block moves.