1. The problem statement, all variables and given/known data At the base of a frictionless icy hill that rises at 25 degree above the horizontal, a toboggan has a speed of 12 m/s toward the hill. How high vertically above the base will it go before stopping? 2. Relevant equations Work and Kinetic energy theorem 3. The attempt at a solution W = −mgy, where y is the vertical height. −mgy=−1/2 mv2 and therefore y equals v2/2g it means vertical height is independent of slope. Is this correct answer?? Bcoz if i assume that slope is zero then also it should reach the vertical height given by the above equation. Kindly clarify.