Work done by internal forces in gravitation

AI Thread Summary
The discussion revolves around calculating the work done by internal forces when two bodies of masses M and m move towards each other under gravitational influence. Initially, the potential energy when they are R apart is -GMm/R, and when they are x apart, it is -GMm/x. The change in potential energy, which represents the work done by internal conservative forces, is calculated as GMm(1/x - 1/R). There is a debate about whether the work done by internal forces is always zero, but the Work Energy theorem clarifies that it should be considered in this context. Ultimately, the work done by internal forces is not zero and is linked to the change in kinetic energy.
pritamthakur
Messages
1
Reaction score
0

Homework Statement


Two bodies of mass M and m separated by a distance 'R' are released and they move towards each other under the influence of gravity . What is the work done by internal forces (considering the 2 bodies as a system) when they are at a distance 'x' apart ?

The Attempt at a Solution



When they are at a distance R apart their potential energy = -GMm/R . When they are at a distance x apart their P.E = -GMm/x. So change in P.E = GMm(1/x-1/R) . That should be the change in K.E = Work done by the internal conservative force. But isn't work done by internal force always zero . Maybe , I am confused .
 
Physics news on Phys.org
No you use the Work Energy theorem where work of internal forces is taken into consideration.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top