Work Done by Movers: Calculating Force Needed for Crate

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To calculate the work done by movers pushing a 160-kg crate 10.3 m across a rough floor with a coefficient of friction of 0.50, the relevant formula for friction is F_friction = u * N, where N is the normal force. Since the crate is not accelerating, the force exerted by the movers must equal the frictional force. The normal force (N) is equal to the weight of the crate, which is 160 kg multiplied by the acceleration due to gravity (approximately 9.81 m/s²). The work done can then be calculated using the formula Work = Force * Distance. Understanding these concepts and formulas is essential for solving the problem effectively.
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How much work did the movers do (horizontally) pushing a 160-kg crate 10.3 m across a rough floor without acceleration, if the effect coefficient of friction was 0.50?

I don't know an equation that matches up with the given info, could someone get me started?
 
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It involves work and friction. Do you have formulas for those concepts?
 
Well the only formula on my formula sheet for class involving friction is Ffriction=u times N and I don't even know what that means...: /
 

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