Work Done by Worker: Calculating Force of a Pushed Cart

[PepeF.]

Homework Statement

a shopper pushes a cart with a force of 35N directed at an angle of 26' downward from the horisontal.

find the work done if he pushes the cart for 50.7m

Homework Equations

w=(f)(cos 0)(Δx)
f= w/(cos 0)(Δx)

The Attempt at a Solution

i did but i got it wrong
i did: the equation and got it wrong then i tried to find force because i though it was a word problem but was not successful please help

 

[method_man]

Are you sure you get it wrong. http://mravis.com/planbook/PreAP%20Physics/Jan082008/PAP%20Work%20and%20Energy%20WS.pdf" you have got similar problem (number 7).

 

[kerimek]

Hello, thank you for sharing your attempt at a solution. It looks like you are on the right track with using the equation for work, which is W = FcosθΔx. In this equation, F represents the force, θ represents the angle at which the force is applied, and Δx represents the displacement.

To solve this problem, we first need to find the force applied by the shopper. We can use the given information that the force is 35N and is directed at an angle of 26' downward from the horizontal. To find the horizontal component of the force, we can use trigonometry. The horizontal component of the force is given by Fcosθ, which in this case would be 35cos26° = 31.9N.

Now, we can use this value for the force in our equation for work. The displacement, Δx, is given as 50.7m in the problem. Plugging in the values, we get W = (31.9N)(50.7m) = 1619.53 J. This is the work done by the shopper in pushing the cart for 50.7m.

I hope this helps clarify the solution for you. Keep up the good work!