Work Done on Proton by +3microC Charge: Find V at 50cm & 35cm

AI Thread Summary
The discussion focuses on calculating the work done on a proton as it moves from 50 cm to 35 cm away from a stationary +3 microcoulomb charge. The work is determined using the formula W=qV, where V is the change in electric potential calculated from V=kq/r. The initial calculations for V were attempted but resulted in an incorrect work value, with the correct answer being 3.7E-15 joules. For the second part, the speed of the proton at infinity can be derived once the correct potential is established. The participants emphasize the importance of accurately calculating the electric potential for both parts of the problem.
kitkat2950
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A proton is moved at a constant velocity towards a stationary +3micro coloumb point charge that cannot move. The proton is initially 50 cm away from the point charge and the proton is moved until it is 35 cm away from the point charge.
A) How much work was done on the proton?
B) If released from rest when 35 cm away from the point charge, what will be the speed of the proton at infinity.

For A, I know W=qV where q is the charge and i think v is the change in electric potential energy. And I thought that V=kq/r and k=9E9. I did V=(9E9)(1.6e-19C)/.35m and V=(9E9)(1.6E-19C)/.5m. Then I subtracted to find the change in potential energy. I then multiplied that by the charge, but my answer was wrong. The right answer is 3.7E-15.

For B, I think once I find V, I can figure out the rest.
 
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kitkat2950 said:
A proton is moved at a constant velocity towards a stationary +3micro coloumb point charge that cannot move. The proton is initially 50 cm away from the point charge and the proton is moved until it is 35 cm away from the point charge.
A) How much work was done on the proton?
B) If released from rest when 35 cm away from the point charge, what will be the speed of the proton at infinity.

For A, I know W=qV where q is the charge and i think v is the change in electric potential energy. And I thought that V=kq/r and k=9E9. I did V=(9E9)(1.6e-19C)/.35m and V=(9E9)(1.6E-19C)/.5m. Then I subtracted to find the change in potential energy. I then multiplied that by the charge, but my answer was wrong. The right answer is 3.7E-15.

For B, I think once I find V, I can figure out the rest.
Which quantity did you multiply the change in potential by?
 
kitkat2950 said:
For B, I think once I find V, I can figure out the rest.
Well it is a point charge you are dealing with. So V should be relatively easy to calculate.
 
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