Work Done on Stone: 0 Kinetic Energy Change

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The work done on a stone with a mass of 2.5 kg, falling at a constant speed of 2 m/s in a liquid, is zero due to no change in kinetic energy. The stone reaches terminal velocity, indicating that the net force acting on it is zero. Therefore, according to the work-energy principle, the work done is calculated as zero. The discussion also includes an apology for posting in the wrong section. Overall, the conclusion is that no work is done on the stone while it moves at constant speed.
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Homework Statement


A stone has mass 2.5 kg is placed in a liquid. It falls with constant speed 2 ms-1 and travels 80 cm. Find the work done


Homework Equations


W = delta Ek


The Attempt at a Solution


The work done = 0 because there is no change in kinetic energy. Am I right?

Thanks
 
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Oh my god..I'm so sorry I've posted oin the wrong section. Please move this thread to the appropriate section. I'm really sorry

Thanks
 
The stone is moving in liquid with terminal velocity. So the net force acting on it zero. So the work done on the stone is zero.
 
Thanks a lot rl.bhat ! :smile:

And I'm sorry for posting in wrong section.
 

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