Work, Energy & Friction: How Do They Fit?

AI Thread Summary
Work is defined as the energy transferred to a system, and in the case of lifting a 2kg ball, the work done results in both potential and kinetic energy. Lifting the ball with a force of 25N over 5 meters yields a total work of 125J, with 100J converted to potential energy and 25J to kinetic energy. When dragging the ball against friction, the work done must account for the opposing friction force, which converts energy into heat rather than storing it as potential energy. The discussion highlights the difference between conservative forces like gravity, which store energy, and non-conservative forces like friction, which dissipate energy. Understanding these distinctions is crucial for calculating mechanical energy accurately.
c77793
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I've always seen Work as an extra mechanic energy given to the system... but i really can't figure it out :

If we lift a 2kg ball, that's steady, using g as 10m/s², with 25N, we'll have a 5N up resultant force...

after its 5meters up, the resultant work will be 25J (5N.5m), but the potential energy by itself will be 100J (20kgx10m/s²x5m) and the kinetic energy will be 25J (i found it using the F=ma to discover de aceleration and then using torricelli's formula..)..

How can I give 25J to a system and it become 125J?

If the same ball were dragged along the floor, with 25N, and a friction force of 20N , after 5 meters, the resultant work would be 25J, the same as the extra mechanic energy ... can someone help me?
 
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you still used 25N to lift, so the work done by you would be:

25 N*5 m = 125 J

From that 125 J of work, 100 was stored as potential energy, the other 25 is being used as kinetic energy (since the object is still moving).

If you are dragging a ball against friction, you are doing work against the friction, so the work is 45 N * 5 m = 225 J.

I don't know what "extra mechanical energy" means.
 
But shouldn't I use the Resultant force?

as if it were horizontally and the Gravity force were the friction force?
 
well, the friction will do a work of -100J (once its againts the movement) and the force will do a 125 work... the work will be 25, as if it were a 5N force only... I learned that way, is it wrong?
 
c77793 said:
But shouldn't I use the Resultant force?

as if it were horizontally and the Gravity force were the friction force?

It depends on the exact question. If you're asking how much work you do to pull it along the ground then you are doing work against friction, so that must be added.
 
c77793 said:
well, the friction will do a work of -100J (once its againts the movement) and the force will do a 125 work... the work will be 25, as if it were a 5N force only... I learned that way, is it wrong?

Well no, the wording you've used here makes it right. You specified which force did how much work and used the qualifier "as if". So your statements here are correct.
 
I think I got it... when it comes to friction, the energy becomes heat, so we just cut it off the equation to calculate the Mechanical Energy...

but when it comes to Gravity force, the energy becomes potential energy, so we add it to the equation... is it right?
 
c77793 said:
I think I got it... when it comes to friction, the energy becomes heat, so we just cut it off the equation to calculate the Mechanical Energy...

but when it comes to Gravity force, the energy becomes potential energy, so we add it to the equation... is it right?

Yes, that's true. Gravity is a conservative force, friction is not.
 
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