How Does Spring Constant Affect Work Done on a Stretched Spring?

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The discussion focuses on calculating the work done by a spring with a spring constant of 15 N/cm when stretched. To find the work done on the cage when the spring is stretched by 7.6 mm, the formula W = 0.5KX^2 is applied, where K is the spring constant and X is the displacement in centimeters. The conversion of 7.6 mm to 0.76 cm is noted as necessary for the calculations. The additional work done when stretching the spring by another 7.6 mm can be calculated using the same formula, considering the new total displacement. Understanding these calculations is crucial for solving the homework problem effectively.
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Homework Statement



A spring with a spring constant f 15 N/cm has a cage attached to one end.
a) How much work does the spring force do on the cage when the spring is stretched from its relaxed length by 7.6 mm?
b) How much additional work is done by the spring force when the spring is stretched by additional 7.6 mm?


I converted the 7.6 mm to .76 cm but I aint sure on the question for this. Is it W - 1/s x 15 x .76 ?
 
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use W=0.5KX^2 to find the work done..
 
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