- #1
rueberry
- 5
- 0
How much work is required to stop a 1000 kg car traveling at 100 km/hr?
I was going to use KE=1/2mv^2 , since the work should equal the KE, assuming no friction.
I have: =1/2(1000 kg)(100km/hr)^2
I was using dimensional analysis to make the conversion to m/s, so I end up with J, but I think I'm doing something wrong in the conversion.
(1000 km/hr)(1000 m/1 km)(3600 sec/1 hr)
I was going to use KE=1/2mv^2 , since the work should equal the KE, assuming no friction.
I have: =1/2(1000 kg)(100km/hr)^2
I was using dimensional analysis to make the conversion to m/s, so I end up with J, but I think I'm doing something wrong in the conversion.
(1000 km/hr)(1000 m/1 km)(3600 sec/1 hr)