Work Needed to Accelerate 2008 Dodge Viper SRT

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Homework Statement



The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>


Homework Equations



I am confused on what formula to use


The Attempt at a Solution



I did.. KE=1/2mv^2... so...1/2(1560KG)(30m/s)^2... is this correct?
 
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lolcatz said:

Homework Statement



The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>

Homework Equations



I am confused on what formula to use

The Attempt at a Solution



I did.. KE=1/2mv^2... so...1/2(1560KG)(30m/s)^2... is this correct?

Yes.

Out of interest, what other formulae do you have at your disposal?]

edit: I didn't read your question properly, I do apologise.

this is the energy transfer, not power.

For power there are several equations available:

[tex]W = F \cdot \Delta d[/tex]

[tex]P(t) = F(t) \cdot v(t)[/tex]

[tex]P = \frac{W}{\Delta s}[/tex]

and also remember that horsepower can be converted to SI units of power.
 
Last edited:
its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?
 
lolcatz said:
its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?

That is correct, the units of work are Watts; [tex]W[/tex], or in other terms:

[tex]Js^{-1}[/tex];

[tex]kg \cdot m^{2} s^{-3}[/tex];

[tex]N \cdot ms^{-1}[/tex]As you can see, all of these units involve a measurement of time, so are you sure there is not mention of time in the question?

edit: you are confusing me haha; the units of work ARE joules, so the work done is the [tex]E_{k}[/tex]
 
Last edited:
well ...


part B of the question says... if the car does this work in a time of 4 seconds, what power did the car develop?
could you use this on part A?
 
haha, read my edits please =]