Work Needed to Accelerate 2008 Dodge Viper SRT

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To determine the work needed for a 2008 Dodge Viper SRT to accelerate from rest to 30 m/s, the kinetic energy formula KE = 1/2 mv² is appropriate. With a mass of 1560 kg, the calculation yields the work done as KE = 1/2(1560 kg)(30 m/s)². There is some confusion regarding the distinction between work and power, as work is measured in joules, while power is measured in watts. Additionally, the discussion highlights the importance of considering time when calculating power, particularly in relation to part B of the question, which asks for power developed over 4 seconds. Overall, the key focus is on applying the correct formulas for work and power in the context of the Viper's acceleration.
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Homework Statement



The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>


Homework Equations



I am confused on what formula to use


The Attempt at a Solution



I did.. KE=1/2mv^2... so...1/2(1560KG)(30m/s)^2... is this correct?
 
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lolcatz said:

Homework Statement



The 2008 dodge viper srt uses a v-10 engine to develop more than 600HP of the power,

question- If the mass of the viper is 1560 kg, what work must be done by the car to accelerate from rest to 30m/s>

Homework Equations



I am confused on what formula to use

The Attempt at a Solution



I did.. KE=1/2mv^2... so...1/2(1560KG)(30m/s)^2... is this correct?

Yes.

Out of interest, what other formulae do you have at your disposal?]

edit: I didn't read your question properly, I do apologise.

this is the energy transfer, not power.

For power there are several equations available:

W = F \cdot \Delta d

P(t) = F(t) \cdot v(t)

P = \frac{W}{\Delta s}

and also remember that horsepower can be converted to SI units of power.
 
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its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?
 
lolcatz said:
its a take home quiz... the formulas stated are... KE, PE, work, power and %lost

i was hesitant because Joules obtained from the KE formula are not units of work? am i correct?

That is correct, the units of work are Watts; W, or in other terms:

Js^{-1};

kg \cdot m^{2} s^{-3};

N \cdot ms^{-1}As you can see, all of these units involve a measurement of time, so are you sure there is not mention of time in the question?

edit: you are confusing me haha; the units of work ARE joules, so the work done is the E_{k}
 
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well ...


part B of the question says... if the car does this work in a time of 4 seconds, what power did the car develop?
could you use this on part A?
 
haha, read my edits please =]
 
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