Work phythagorean theorem Question

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To determine the work needed to stand a 3.4m long, 2.0m wide, and 180kg marble slab on its end, the correct approach involves calculating the force and the vertical distance it needs to be raised. The force is calculated as 180kg multiplied by 9.8m/s², resulting in 1764N. The distance the slab rises is the height of the slab when standing, which is 3.4m, leading to a work calculation of 1764N multiplied by 3.4m, equating to approximately 6000 J, not 3000 J as initially thought. For the incline problem, the work done against friction is added to the gravitational work, resulting in a total of 3990 J, which clarifies the need to account for both forces when calculating work. Understanding the relationship between force, distance, and the effects of friction is crucial for solving these physics problems effectively.
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this is drivnig me nuts I've doen eveyrthin gon the worksheet but this is a weird one


A unifrom rectangular marble slab is 3.4m long and 2.0m wide. It has a mass of 180KG. If it is originally lying on the flag ground, how much work is needed to stand it on end.

I know work = force X distance
and to get force i multiply 180X9.8 like I've doen in all the other questions
but what's teh distance here it rises, it ried phythagorean theorem to get the distance and all these weird aways
but the asnwer should be
3000 J
dont nkow what to do!
thanks
 
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and another
Q1 was)
A 200 kg cart is pushed slowly up an incline. How much work does the pushing force do in moivng the cart up to a platorm 1.5m above the starting point if frciton is negligible

that was fairly easy, (200X9.8) = 1960 X 1.5 = 2940 J

Q2 is )
Repeat Q1 if the distance along hte incilne to the platofrom is 7m and a fricotin force of 150N opposes the motion.
I didnt know how to handle this, but i see doing 7X150 = 1050
and adding that to the first asnwer 2940J gives me the right answer
3990
can anyone expalin why this worked?
i thoguht id have to do 1960X7 instead and what would i do with force
 
please ppl!
 
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