A box of mass 49 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0.60. A woman pushes horizontally against the box with a force of 628 N until the box attains a speed of 3 m/s.
What is the work done by the woman on the box?
What is the CM-work done by the friction force on the box?
W=F (delata x)
W(f)= uN (delta x)
The Attempt at a Solution
Since work is in joules, I tried calculating it by multiplying force by velocity squared but that gave me a wrong answer. If I had the right answer for work I'd solve for delta x and use that to solve for work of friction