1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Working out freq for circuit to be in phase

  1. Oct 10, 2008 #1
    1. The problem statement, all variables and given/known data

    AC circuit Vs is 100V 50Hz and is used as reference.
    there are two impedences in parallel, made up of a 5ohm resistor and an inductor reactance = +j2 ohm that is parallel with 3 ohm resistor and a inductor reactance = -j3 ohm (though I though negative imaginary part was for capactance???)

    voltage across the 3 ohm resistor is 45 Volts

    The branch with the resistor and inductor is called I1 , branch with resistor and capacitor is I2
    Is is the total current from supply before the parallel branch.

    Please see attachment of circuit

    2. Relevant equations

    I2 = v/I angle = arctan x/r

    Is = Vs/Zt = Vs * 1/ (Z1 parallel Z2) = Z1Z2/(Z1+Z2)

    3. The attempt at a solution

    I2 = 45/3 =15A angle = artan -3/3 = -45 degrees

    magnitude of Vs = 15 * sqrt(3^2+3^2) = 63.64 volts

    Z1 = 5+2j = 5.385 angle 21.8 deg Z2 = 3-3j = 4.234 angle -45 deg

    Z1//Z2 = {(5.385 angle 21.8) * ( 4.234 angle -45)}/ {(5+2j)+(3-3j)}

    Z1//Z2 = 22.849 angle -23.2 deg / 8.06 angle -7.125

    Z1//Z2 = 2.835 angle -16.075 deg

    Is = 63.64/(2.835 angle -16.075) = 22.45 angle -16.08 deg

    From here is where I'm lost on how to calculate the frequency needed to get this circuit to have current and voltage in phase (zero degrees)

    Attached Files:

  2. jcsd
  3. Oct 10, 2008 #2


    User Avatar

    For voltage and current to be in phase, the impedance must be a pure resistance, so the imaginary part of your impedance must be zero.
    Since you know the impedances of capacitor and inductor at 50Hz, you can calculate their values.
    Write Z1, Z2 and Z1//Z2 as functions of the known values of resistances, inductances and capacitances and the unknown value of frequency. Then calculate the frequency for which the imaginary part of the impedance is zero.
  4. Oct 10, 2008 #3
    I had worked out the inductance values of components for the known frequency of 50Hz howerver I'm unsure what you mean by "write Z1, Z2 and Z1//Z2 as functions of the known values of resistance, and inductance capacitance and the unknonwn value of frequency".
  5. Oct 10, 2008 #4


    User Avatar

    If you call f the frequency, [tex]Z_1=R_1 + 2\pi f L_1[/tex].
    You have a similar expression for [tex]Z_2[/tex] and for the parallel of the two. The only unknown is f, that you calculate by making the imaginary part of the impedance equal to zero.
  6. Oct 11, 2008 #5
    So I have Z1 = 5 + 2pifL and Z2 = 3 + 2pifl but what is the expression for Z1//Z2 with using the above value of Z1 and Z2 ??
  7. Oct 11, 2008 #6


    User Avatar

    [tex]Z_1 = 5 +j2\pi f L[/tex]
    [tex]Z_2 = 3+\frac{1}{j2\pi f C}[/tex]

    [tex]Z_1 // Z_2 = \frac{Z_1 Z_2}{Z_1 + Z_2}[/tex]
  8. Oct 11, 2008 #7
    from that i get this

    z_1 //z_2 = \frac{{(5 + j2\pi fL) \times (3 + j\frac{1}{{2\pi fC}})}}{{(5 + j2\pi fL) + (3 + j\frac{1}{{2\pi fC}})}} \\
    = \frac{{15 + j\frac{5}{{2\pi fC}} + j6\pi fL + \frac{L}{C}}}{{8 + j2\pi fL + j\frac{1}{{2\pi fC}}}} \\
    Again I'm stuck. Could you please give me some more assistance thankyou.
    Last edited: Oct 11, 2008
  9. Oct 12, 2008 #8


    User Avatar

    Multiply the numerator and denominator of the fraction by the complex conjugate of the denominator. In this way only the numerator will be complex.
    Equate the imaginary part of the numerator to zero and calculate the value of f.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Working out freq for circuit to be in phase
  1. 3 Phase Short Circuit (Replies: 0)