Would this force be large enough to lift a 60 kg person?

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The average force exerted on a tennis ball served at 62.0 m/s with a mass of 0.0600 kg and contact time of 0.0200 s is calculated to be 186 N. This force is significantly lower than the approximately 600 N required to lift a 60 kg person. The calculations involve determining the ball's momentum and applying the formula for average force based on the change in momentum over time. The conclusion is that the force generated by the tennis ball is not large enough to lift a 60 kg individual. Therefore, the average force on the ball is insufficient for that purpose.
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A tennis ball may leave the racket of a top player on the serve with a speed of 62.0 m/s. If the ball's mass is 0.0600 kg and it is in contact with the racket for 0.0200 s, what is the average force on the ball?

Would this force be large enough to lift a 60 kg person?
large enough or
not large enough

I got .0600x62=3.72

.0200/3.72=.00537

I don't think that is right because that seems way to small but I don't know what I am missing...if it is incorrec that is.
 
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W = mg so the force needed to lift a 60kg person will be ~ 600N.
a = 62/0.02 = 3100
F = ma = 0.06*3100 = 186

So it is not large enough.
 
The force on the ball equals the change of its momentum with respect to time.

F_{ave}=\frac{\Delta P}{\Delta t}

You already calculated its momentum when it leaves the racket, if we assume the ball is stationary before it is hit you can get the average force from the above formula.
 
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